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Hortonworks Hadoop 2.0 Certification exam for Pig and Hive Developer Sample Questions:

1. Which one of the following statements describes the relationship between the NodeManager and the ApplicationMaster?

A) The ApplicationMaster starts the NodeManager outside of a Container
B) The ApplicationMaster starts the NodeManager in a Container
C) The NodeManager creates an instance of the ApplicationMaster
D) The NodeManager requests resources from the ApplicationMaster

2. You have just executed a MapReduce job. Where is intermediate data written to after being emitted from the Mapper's map method?

A) Intermediate data in streamed across the network from Mapper to the Reduce and is never written to disk.
B) Into in-memory buffers that spill over to the local file system (outside HDFS) of the TaskTracker node running the Reducer
C) Into in-memory buffers that spill over to the local file system of the TaskTracker node running the Mapper.
D) Into in-memory buffers on the TaskTracker node running the Mapper that spill over and are written into HDFS.
E) Into in-memory buffers on the TaskTracker node running the Reducer that spill over and are written into HDFS.

3. Can you use MapReduce to perform a relational join on two large tables sharing a key? Assume that the two tables are formatted as comma-separated files in HDFS.

A) Yes, so long as both tables fit into memory.
B) Yes, but only if one of the tables fits into memory
C) No, MapReduce cannot perform relational operations.
D) Yes.
E) No, but it can be done with either Pig or Hive.

4. MapReduce v2 (MRv2/YARN) is designed to address which two issues?

A) Resource pressure on the JobTracker.
B) HDFS latency.
C) Reduce complexity of the MapReduce APIs.
D) Standardize on a single MapReduce API.
E) Ability to run frameworks other than MapReduce, such as MPI.
F) Single point of failure in the NameNode.

5. For each intermediate key, each reducer task can emit:

A) One final key-value pair per value associated with the key; no restrictions on the type.
B) As many final key-value pairs as desired, as long as all the keys have the same type and all the values have the same type.
C) As many final key-value pairs as desired. There are no restrictions on the types of those key-value pairs (i.e., they can be heterogeneous).
D) As many final key-value pairs as desired, but they must have the same type as the intermediate key-value pairs.
E) One final key-value pair per key; no restrictions on the type.

Solutions: