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Oracle Introduction to Oracle9i: SQL Sample Questions:

1. Examine the structure of the EMPLOYEES and NEW_EMPLOYEES tables:
EMPLOYEES EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) HIRE_DATE DATE
NEW_EMPLOYEES EMPLOYEE_ID NUMBER Primary Key NAME VARCHAR2(60) Which MERGE statement is valid?

A) MERGE new_employees c USING employees e ON (c.employee_id = e.employee_id) WHEN EXISTS THEN UPDATE SET c.name = e.first_name ||','|| e.last_name WHEN NOT MATCHED THEN INSERT VALUES (e.employee_id, e.first_name ||', '||e.last_name);
B) MERGE INTO new_employees c USING employees e ON (c.employee_id = e.employee_id) WHEN MATCHED THEN UPDATE SET c.name = e.first_name ||','|| e.last_name WHEN NOT MATCHED THEN INSERT VALUES (e.employee_id, e.first_name ||', '||e.last_name);
C) MERGE new_employees c FROM employees e ON (c.employee_id = e.employee_id) WHEN MATCHED THEN UPDATE SET c.name = e.first_name ||','|| e.last_name WHEN NOT MATCHED THEN INSERT INTO new_employees VALUES (e.employee_id, e.first_name ||', '||e.last_name);
D) MERGE INTO new_employees c USING employees e ON (c.employee_id = e.employee_id) WHEN EXISTS THEN UPDATE SET c.name = e.first_name ||','|| e.last_name WHEN NOT MATCHED THEN INSERT VALUES(e.employee_id, e.first_name ||', '||e.last_name);

2. The STUDENT_GRADES table has these columns: STUDENT_ID NUMBER(12)
SEMESTER_END DATE
GPA NUMBER(4,3)
The registrar requested a report listing the students' grade point averages (GPA) sorted from highest grade point average to lowest.
Which statement produces a report that displays the student ID and GPA in the sorted order requested by the registrar?

A) SELECT student_id, gpa FROM student_grades ORDER BY gpa DESC;
B) SELECT student_id, gpa FROM student_grades SORT ORDER BY gpa;
C) SELECT student_id, gpa FROM student_grades SORT ORDER BY gpa DESC;
D) SELECT student_id, gpa FROM student_grades ORDER BY gpa ASC;
E) SELECT student_id, gpa FROM student_grades ORDER BY gpa;
F) SELECT student_id, gpa FROM student_grades SORT ORDER BY gpa ASC;

3. The CUSTOMERS table has these columns:

Which statement finds the rows in the CUSTOMERS table that do not have a postal code?

A) SELECT customer_id, customer_name FROM customers WHERE postal_code = '________';
B) SELECT customer_id, customer_name FROM customers WHERE postal code IS NVL;
C) SELECT customer_id, customer_name FROM customers WHERE postal_code = NULL;
D) SELECT customer_id, customer_name FROM customers WHERE postal_code CONTAINS NULL;
E) SELECT customer_id, customer_name FROM customers WHERE postal_code IS NULL;

4. The database administrator of your company created a public synonym called HR for the HUMAN_RESOURCES table of the GENERAL schema, because many users frequently use this table.
As a user of the database, you created a table called HR in your schema. What happens when you execute this query?
SELECT *
FROM HR;

A) You obtain the results retrieved from the HR table that belongs to your schema.
B) You obtain the results retrieved from the public synonym HR created by the database administrator.
C) You get an error message because you cannot retrieve from a table that has the same name as a public synonym.
D) You obtain the results retrieved from both the public synonym HR and the HR table that belongs to your schema, as a FULL JOIN.
E) You obtain the results retrieved from both the public synonym HR and the HR table that belongs to your schema, as a Cartesian product.

5. Evaluate this SQL statement:
SELECT e.employee_id, (.15* e.salary) + (.5 * e.commission_pct)
+ (s.sales amount * (.35 * e.bonus)) AS CALC_VALUE FROM employees e, sales s WHERE e.employee_id = s.emp_id;
What will happen if you remove all the parentheses from the calculation?

A) There will be no difference in the value displayed in the CALC_VALUE column.
B) The value displayed in the CALC_VALUE column will be higher.
C) An error will be reported.
D) The value displayed in the CALC_VALUE column will be lower.

Solutions: